This is where I collect all of my blunders, flaws, fallacies, miscalculations, inaccuracies, and other miscellaneous grammatical and mathematical howlers in Basic Discrete Mathematics. The name of the person who found the erratum is listed at the end. RK is me.
First printing errata
- p. 8: “invitation” should read “invention” (E. Schwab)
- p. 12. Example 1.3.9. “…and the consequent is ‘x is human.'” should read “…and the consequent is ‘x is mortal.'” (RK)
- p. 64. Exercise 2.9.3. The argument is not valid. You can show this is not a valid argument by doing a truth table. (DRE)
- p. 114. Fig 3.37. The set/circle should be labeled . (RK)
- p. 125. “” should read “” (C. Parkes)
- p. 266. Last paragraph. should read . (O. Toller)
- p. 285. Exercise 7.1.6. Add “Note that the bus does not traverse a road twice.” (O. Toller)
- p. 329. Last line: “Low-and-behold” should read “Lo-and-behold.” (O. Toller)
- p. 390. Exercise 8.12.14. should read “…one of the candidates given that the committee…”
- p. 391. Line 2: should read “more lively.” (O. Toller)
- p. 422. Example 10.2.1: Add “He fires 4 rounds.” (O. Toller)
- p. 404. Eq. (9.3). Replace Loses with Losses. (RK)
- p. 489. 4th & 5th lines of Proof, 1st term should be , not . Same issue in 2 places in Exercise B.4.2. (E. Schwab)
- p. 498. Solution to 1.3.6 (d) should be T and not F. (RK & MAE106 2017)
- p. 511. Solution to 1.7.9 (c) is missing. The contrapositive is . The inverse is . The converse is . (MS — MAE106 2017)
- p. 526. Solution to 3.3.8. (b) (i) “1, 2, 4, 5, 6” should read “1, 2, 3, 4, 5, 6”. (RK)
- p. 537. Solution 5.2.9. It should read as the following. For the first digit, it can be ; that is, there are 9 choices for the first digit. In order for the number to be divisible by or , the last digit must be , or . Thus, for the second digit there are 4 choices; that is, you can select from , , , or . Therefore, there are
numbers that are not divisible by or .
- p. 537. Solution 5.2.10 (b). There is one less choice but there is also the additional choice of 0. If the last digit is a 1, then
If the last digit is a 3, then
If the last digit is a 5, then
By the Sum Principle, there are ways to do this.
- p. 542. Solution 5.4.12 (b). The solution given in the book overcounts. It should start at 10 instead of 11, since Trent is one of the choices that is not available. The solution should be
(RK & C. H. Tsai)
- p. 546. Solution 5.7.10. The solution given in the book overcounts the number of possible hands. Consider cases. Case 1: which is .Case 2: which is .Case 3: which is .Case 4: which is .By the Sum Principle, there are ways to select the hand as required. (HT — MAE106 2018)
- p. 586. Solution to 6.9.9. The solution given is incorrect since it does not consider the distance traveled by the basketball up and down; the solution is correct for the distance traveled in the downward direction. Replace solution with the following: To help understand the problem, draw a diagram.
The total distance, both up and down, the basketball traveled is